Problem: A baseball/forearm system is at rest.
It is acted on by four different forces: the weight of the forearm, the weight of the baseball, the bicep force, and a force from the upper arm bone.
Given Information:
length of forearm = L = 13 cm
elbow to bicep distance = d = 2 cm
mass of forearm = M = 3 kg
mass of baseball = m = 2 kg
Questions:
a.) How large is the force exerted by the bicep?
c.) The force exerted by the upper arm bone on the forearm must be?
Ok, so far all I know is that the total Torque and Forces (x and y component) must equal to zero. But, I am having trouble with figuring out the Force of the upper arm bone and the force of the bicep.
Static Equilibrium Problem?
2g at .13m + 3g at .13/2 m = F at .02m
so F=.13(2+1.5)g/.02=223N c)
Assuming the bicep muscle forms a triangle with the elbow the right angle and both sides 2cm=.02m. This would be a 45deg angle. So the tension in the bicep is 223/sin45
=315.3N a)
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