Crane in static equilbrium?

A crane of mass m,c = 3200 kg supports a load of m,l = 11900 kg. The crane is pivoted with a frictionless pin at A and rests against a smooth support at B. Find the reaction forces at A and B. (want answers in horizontal and vertical components)





The figure can be found at http://www.webassign.net/serpop/p10-32al...





So I figured that the pin can provide both a horizontal and vertical reaction force, but the support can only provide a horizontal reaction force. Therefore, I said F,By = 0 N, which is correct.





I also did the sum of the forces in the y direction is equal to F,Ay - m,c*g - m,l * g, which equals 0. From this, I solved F,Ay = 147980 N. This is also correct.





Where I need help is figuring out F,Ax and F,Bx. I am confused as to what the free body diagram would look like for these two components. In addition, I believe I need to use a sum of the torques equation to figure them out, but I do not know how to form this equation. Please help. Thanks.

Crane in static equilbrium?
You have done well so lets put this puppy to sleep





Reaction at A equal to reaction at B however they appose each other


Fax=Fbx





Moment about A is


2 mc g - 1 Fbx + 6 mf g = 0


Fbx = g(2 mc + 6 mf )


Fbx= 9.81(2 x 3,200 + 6 x 11,900)


Fbx=763,218 N


so


Fax= -763,218 N





Have fun!