A 50.0 kg child stands at the rim of a merry-go-round of radius 1.70 m, rotating with an angular speed of 2.70 rad/s.
(a) What is the child's centripetal acceleration?
_______ m/s2
(b) What is the minimum force between her feet and the floor of the merry-go-round that is required to keep her in the circular path?
________ N
(c) What minimum coefficient of static friction is required?
_________
Is the answer you found reasonable? In other words, is she likely to be able to stay on the merry-go-round?
Phyics: Circular Motion #4?
This is also fairly straightforward and is solved using the equation a= v^2/r. Part b is solved using F=ma, with the a from the previous question. Part c is found using F=mu(m)(g) where mu is the coefficient of friction. Please let me know if you need anymore help.
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