The centripetal acceleration?

A 50.0 kg child stands at the rim of a merry-go-round of radius 2.30 m, rotating with an angular speed of 3.35 rad/s.


(a) What is the child's centripetal acceleration?


m/s2





(b) What is the minimum force between her feet and the floor of the carousel that is required to keep her in the circular path?


N





(c) What minimum coefficient of static friction is required?








Is the answer you found reasonable? In other words, is she likely to stay on the merry-go-round?


yes


no

The centripetal acceleration?
The equations will be in your text book, but here they are:





(a) the centripetal acceleration is


a = r * w^2


where r is the radius, w is the angular speed





(b) F = m * a, use "a" calculated in part (a)


and m is the child's mass





(c) F = u * m * g


where


F is the force calculated in part (b)


u = coef. of static friction


g = acceleration due to gravity


Solve that equation for "u" to get your answer